PAT-A-1013-Reversible Primes

A reversible prime in any number system is a prime whose “reverse” in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime.

Now given any two positive integers N (<105) and D (1<D≤10), you are supposed to tell if N is a reversible prime with radix D.

Input Specification:

The input file consists of several test cases. Each case occupies a line which contains two integers N and D. The input is finished by a negative N.

Output Specification:

For each test case, print in one line Yes if N is a reversible prime with radix D, or No if not.

Sample Input:

1
2
3
4
73 10
23 2
23 10
-2

Sample Output:

1
2
3
Yes
Yes
No

Code

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#include <iostream>
#include <cmath>
using namespace std;

bool isPrime(int n){
if(n<=1)return false;
int sqr=(int)sqrt(1.0*n);
for(int i=2;i<=sqr;i++)
if(n%i==0)return false;
return true;
}


int main(){
int change[200];
int n,d,count;
while(scanf("%d",&n)!=EOF){
if(n<0)break;
scanf("%d",&d);
if(isPrime(n)){
count=0;
//进行进制转化(按照从左到右低位到高位的存储)
do{
change[count++]=n%d;
n/=d;
}while(n!=0);
//转为10进制
int product=1;
for(int i=count-1;i>=0;i--){
n+=change[i]*product;
product*=d;
}

if(isPrime(n))
printf("Yes\n");
else
printf("No\n");
}else
printf("No\n");
}
return 0;
}

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